Difference between revisions of "First group isomorphism theorem"
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− | |above=<span style="font-size:1.3em;">{{M|1= }}</span>< | + | |above=<div style="overflow:hidden;"><span style="font-size:1.3em;">{{M|1= }}</span></div>Where {{M|\theta}} is an [[group isomorphism|isomorphism]]. |
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Revision as of 17:47, 16 July 2016
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- Note:
- Overview of the group isomorphism theorems - all 3 theorems in one place
- Overview of the isomorphism theorems - the first, second and third are pretty much the same just differing by what objects they apply to
Contents
[hide]First isomorphism theorem | |
θ is an isomorphism. | Where|
Properties | |
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something |
Statement
Let (G,∗) and (H,∗) be groups. Let φ:G→H be a group homomorphism, then[1]:
- G/Ker(φ)≅Im(φ)
- Explicitly we may state this as: there exists a group isomorphism between G/Ker(φ) and Im(φ).
Note: the special case of φ being surjective, then Im(φ)=H, so we see G/Ker(φ)≅H
Proof
Notes
References
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