Every lingering sequence has a convergent subsequence/Proof
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< Every lingering sequence has a convergent subsequence
Revision as of 17:26, 6 December 2015 by Alec (Talk | contribs) (Created page with "{{Todo|Write proof}} '''Proof outline:''' # Take {{M|k_1}} to be the index of any point of the sequence in {{M|B_1(x)}} # Take {{M|k_2}} to be any index AFTER {{M|k_1}} of the...")
TODO: Write proof
Proof outline:
- Take k1 to be the index of any point of the sequence in B1(x)
- Take k2 to be any index AFTER k1 of the sequence in the ball B12(x)
- ...
- Show the sequence (xkn)∞n=1 converges to x
We have exhibited a convergent subsequence, we're done.