Difference between revisions of "Group"

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m (Identity is unique)
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That is both:
 
That is both:
 
* <math>\forall g\in G[e*g=g*e=g]</math>
 
* <math>\forall g\in G[e*g=g*e=g]</math>
* <math>\forall g\in G[e`*g=g*e`=g]</math>
+
* <math>\forall g\in G[e'*g=g*e'=g]</math>
  
But then <math>ee`=e</math> and also <math>ee`=e`<math> thus we see <math>e`=e</math> contradicting that they were different.
+
But then <math>ee'=e</math> and also <math>ee`=e'</math> thus we see <math>e'=e</math> contradicting that they were different.
 
{{End Proof}}
 
{{End Proof}}
 
{{End Theorem}}
 
{{End Theorem}}

Revision as of 10:03, 11 March 2015

Definition

A group is a set [ilmath]G[/ilmath] and an operation [math]*:G\times G\rightarrow G[/math], denoted [math](G,*:G\times G\rightarrow G)[/math] but mathematicians are lazy so we just write [math](G,*)[/math]

Such that the following axioms hold:

Axioms

Words Formal
[math]\forall a,b,c\in G:[(a*b)*c=a*(b*c)][/math] [ilmath]*[/ilmath] is associative, because of this we may write [math]a*b*c[/math] unambiguously.
[math]\exists e\in G\forall g\in G[e*g=g*e=g][/math] [ilmath]*[/ilmath] has an identity element
[math]\forall g\in G\exists x\in G[xg=gx=e][/math] All elements of [ilmath]G[/ilmath] have an inverse element under [ilmath]*[/ilmath], that is

Important theorems

Identity is unique

Proof:


Assume there are two identity elements, [ilmath]e[/ilmath] and [ilmath]e`[/ilmath] with [math]e\ne e`[/math].

That is both:

  • [math]\forall g\in G[e*g=g*e=g][/math]
  • [math]\forall g\in G[e'*g=g*e'=g][/math]

But then [math]ee'=e[/math] and also [math]ee`=e'[/math] thus we see [math]e'=e[/math] contradicting that they were different.