Difference between revisions of "Connected (topology)"

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* we say {{M|A}} is connected if it is connected when considered as a [[subspace topology|topological subspace]] of {{Top.|X|J}}{{rITTMJML}}{{rITTBM}}.
 
* we say {{M|A}} is connected if it is connected when considered as a [[subspace topology|topological subspace]] of {{Top.|X|J}}{{rITTMJML}}{{rITTBM}}.
 
There are equivalent definitions, some are given below.
 
There are equivalent definitions, some are given below.
==Equivalent conditions==
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=={{subpage|Equivalent conditions}}==
To a [[topological space]] {{Top.|X|J}} being connected:
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{{/Equivalent conditions}}
* [[A topological space is connected if and only if the only sets that are both open and closed are the entire space itself and the emptyset]]
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To an arbitrary subset, {{M|A\in\mathcal{P}(X)}}, being connected:
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* Obviously, the only sets being both [[relatively open]] and [[relatively closed]] in {{M|A}} are [[emptyset|{{M|\emptyset}}]] and {{M|A}} itself. (This comes directly from the subspace definition above)
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* [[A subset of a topological space is disconnected if and only if it can be covered by two non-empty disjoint open sets of the space]]
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** Then apply the definition above, a subset is considered connected if it is ''not'' disconnected
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* [[A subset of a topological space is connected if and only if and only if the only two subsets that are both relatively open and relatively closed with respect to the subset are the empty-set and the subset itself]]
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{{Todo|Bottom of page 114 in Mendelson, something about closed sets and connectedness}}
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==See also==
 
==See also==
 
* [[Disconnected (topology)|Disconnected]]
 
* [[Disconnected (topology)|Disconnected]]
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* [[Every continuous map from a non-empty connected space to a discrete space is constant]]
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{{Todo|Flesh out, add more theorems, for example image of a connected set is connected, so forth}}
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==Notes==
 
==Notes==
 
<references group="Note"/>
 
<references group="Note"/>

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There are many ways to state connectedness, and one can just as well start with disconnected and then define "connected" as "not disconnected". I have attempted to pick one and mention the others, do not be put off if you have found another definition! I have started with the most intuitive definition

Definition

Let [ilmath](X,\mathcal{ J })[/ilmath] be a topological space. We say [ilmath]X[/ilmath] is connected if[1]:

There are equivalent definitions, some are given below. Note also, that by this convention the [ilmath]\emptyset[/ilmath] is connected.

Recall the definition of a topological space being disconnected

A topological space, [ilmath](X,\mathcal{ J })[/ilmath], is said to be disconnected if[1]:

  • [ilmath]\exists U,V\in\mathcal{J}[U\ne\emptyset\wedge V\neq\emptyset\wedge V\cap U=\emptyset\wedge U\cup V=X][/ilmath], in words "if there exists a pair of disjoint and non-empty open sets, [ilmath]U[/ilmath] and [ilmath]V[/ilmath], such that their union is [ilmath]X[/ilmath]"

In this case, [ilmath]U[/ilmath] and [ilmath]V[/ilmath] are said to disconnect [ilmath]X[/ilmath][1] and are sometimes called a separation of [ilmath]X[/ilmath].

Of a subset

Let [ilmath]A\in\mathcal{P}(X)[/ilmath] be an arbitrary subset of [ilmath]X[/ilmath], then:

  • we say [ilmath]A[/ilmath] is connected if it is connected when considered as a topological subspace of [ilmath](X,\mathcal{ J })[/ilmath][1][2].

There are equivalent definitions, some are given below.

Equivalent conditions

To a topological space [ilmath](X,\mathcal{ J })[/ilmath] being connected:

To an arbitrary subset, [ilmath]A\in\mathcal{P}(X)[/ilmath], being connected:

See also


TODO: Flesh out, add more theorems, for example image of a connected set is connected, so forth



Notes

  1. We could write this as:
    • [ilmath]\neg(\exists U,V\in\mathcal{J}[U\ne\emptyset\wedge V\neq\emptyset\wedge U\cap V=\emptyset\wedge U\cup V=X])[/ilmath]
    Which is:
    • [ilmath]\forall U,V\in\mathcal{J}[U=\emptyset\vee V=\emptyset\vee U\cap V\ne\emptyset\vee U\cup V\ne X][/ilmath]
    but, whilst completely "true", this is difficult to read and far less intuitive.

References

  1. 1.0 1.1 1.2 1.3 Introduction to Topological Manifolds - John M. Lee
  2. 2.0 2.1 Introduction to Topology - Bert Mendelson







OLD PAGE

Definition

A topological space [math](X,\mathcal{J})[/math] is connected if there is no separation of [math]X[/math][1] A separation of [ilmath]X[/ilmath] is:

  • A pair of non-empty open sets in [ilmath]X[/ilmath], which we'll denote as [math]U,\ V[/math] where:
    1. [math]U\cap V=\emptyset[/math] and
    2. [math]U\cup V=X[/math]

If there is no such separation then the space is connected[2]

Equivalent definition

This definition is equivalent (true if and only if) the only empty sets that are both open in [ilmath]X[/ilmath] are:

  1. [ilmath]\emptyset[/ilmath] and
  2. [ilmath]X[/ilmath] itself.

I will prove this claim now:

Claim: A topological space [math](X,\mathcal{J})[/math] is connected if and only if the sets [math]X,\emptyset[/math] are the only two sets that are both open and closed.


Connected[math]\implies[/math]only sets both open and closed are [math]X,\emptyset[/math]

Suppose [math]X[/math] is connected and there exists a set [math]A[/math] that is not empty and not all of [math]X[/math] which is both open and closed. Then as :this is closed, [math]X-A[/math] is open. Thus [math]A,X-A[/math] is a separation, contradicting that [math]X[/math] is connected.

Only sets both open and closed are [math]X,\emptyset\implies[/math]connected


TODO:



Connected subset

A subset [ilmath]A[/ilmath] of a Topological space [ilmath](X,\mathcal{J})[/ilmath] is connected if (when considered with the Subspace topology) the only two Relatively open and Relatively closed (in A) sets are [ilmath]A[/ilmath] and [ilmath]\emptyset[/ilmath][3]

Useful lemma

Given a topological subspace [ilmath]Y[/ilmath] of a space [ilmath](X,\mathcal{J})[/ilmath] we say that [ilmath]Y[/ilmath] is disconnected if and only if:

  • [math]\exists U,V\in\mathcal{J}[/math] such that:
    • [math]Y\subseteq U\cup V[/math] and
    • [math]U\cap V\subseteq C(Y)[/math] and
    • Both [math]U\cap Y\ne\emptyset[/math] and [math]V\cap Y\ne\emptyset[/math]

This is basically says there has to be a separation of [ilmath]Y[/ilmath] that isn't just [ilmath]Y[/ilmath] and the [ilmath]\emptyset[/ilmath] for [ilmath]Y[/ilmath] to be disconnected, but the sets may overlap outside of {{M|Y}

Proof of lemma:




TODO:



Results

Theorem:Given a topological subspace [ilmath]Y[/ilmath] of a space [ilmath](X,\mathcal{J})[/ilmath] we say that [ilmath]Y[/ilmath] is disconnected if and only if [math]\exists U,V\in\mathcal{J}[/math] such that: [math]A\subseteq U\cup V[/math], [math]U\cap V\subseteq C(A)[/math], [math]U\cap A\ne\emptyset[/math] and [math]V\cap A\ne\emptyset[/math]




TODO: Mendelson p115


Theorem: The image of a connected set is connected under a continuous map




TODO: Mendelson p116



References

  1. Topology - James R. Munkres - 2nd edition
  2. Analysis - Part 1: Elements - Krzysztof Maurin
  3. Introduction to topology - Mendelson - third edition