# A topological space is disconnected if and only if it is homeomorphic to a disjoint union of two or more non-empty topological spaces

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## Contents

## Statement

Let [ilmath](X,\mathcal{ J })[/ilmath] be a topological space, then^{[1]}:

- [ilmath](X,\mathcal{ J })[/ilmath] is disconnected (ie: not connected)
*if and only if*it is homeomorphic to a disjoint union of two or more non-empty topological spaces

## Proof

Grade: C

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The message provided is:

Exercise in Lee's top. manifolds, didn't take me very long to do, note that A topological space is disconnected if and only if there exists a non-constant continuous function from the space to the discrete space on two elements is a useful "precursor" theorem

**This proof has been marked as an page requiring an easy proof**## See also

## References