Difference between revisions of "Floor function"
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# {{M|\forall x\in\mathbb{R}_{\ge 0}\exists\epsilon\in[0,1)\subseteq\mathbb{R}\big[x\eq\Floor{x}+\epsilon\big]}} - the ''[[characteristic property]]'' of the floor function | # {{M|\forall x\in\mathbb{R}_{\ge 0}\exists\epsilon\in[0,1)\subseteq\mathbb{R}\big[x\eq\Floor{x}+\epsilon\big]}} - the ''[[characteristic property]]'' of the floor function | ||
I believe that {{M|3\implies 1}} and {{M|3\implies 2}} might be possible, so these are perhaps in the wrong order. I just wanted to write down some notes before they get put into the massive stack of unfiled paper | I believe that {{M|3\implies 1}} and {{M|3\implies 2}} might be possible, so these are perhaps in the wrong order. I just wanted to write down some notes before they get put into the massive stack of unfiled paper | ||
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+ | This is a corollary to property 3 coupled with the definition (domain and co domain) of the floor [[function]]: | ||
+ | * {{M|\forall x\in\mathbb{R}_{\ge 0}\big[\Floor{x}\le x<\Floor{x}+1\big]}} | ||
+ | This statement is a critical part of finding [[Mdm]]s and was used in: | ||
+ | * [[Mdm of a discrete distribution lemma]] | ||
+ | ** Which at the time of writing ([[User:Alec|Alec]] ([[User talk:Alec|talk]]) 21:20, 21 January 2018 (UTC)) only exists as notes: [[Notes:Mdm of a discrete distribution lemma]] | ||
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{{Definition|Analysis|Real Analysis}} | {{Definition|Analysis|Real Analysis}} |
Latest revision as of 21:20, 21 January 2018
\newcommand{\Floor}[1]{ {\text{Floor}{\left({#1}\right)} } }
Contents
[hide]Definition
For x\in\mathbb{R}_{\ge 0} there is no variation on the meaning of the floor function, however for negative numbers there are varying conventions.
Non-negative
Defined as follows:
- \text{Floor}:\mathbb{R}_{\ge 0}\rightarrow\mathbb{N}_0 by \text{Floor}:x\mapsto\text{Max} (T_x) where T_x:\eq\big\{n\in\mathbb{N}_0\ \big\vert\ n\le x\big\}\subseteq\mathbb{N}_0\subseteq\mathbb{R}_{\ge 0} - note that the maximum element is defined as T_x is always finite.
- This has the property that x\le\Floor{x} .
Negative numbers
Researching this opened my eyes to a massive dispute.... consensus seems to be that x\le \Floor{x} is maintained, rounding is a separate and massive issue!
References
Future work
Properties
- \forall n\in\mathbb{N}_0\subseteq\mathbb{R}_{\ge 0}\big[\Floor{n}\eq n\big], or \text{Floor}\vert_{\mathbb{N}_0}\eq\text{Id}_{\mathbb{N}_0} - its restriction to \mathbb{N}_0 is the identity map on \mathbb{N}_0
- \forall x,y\in\mathbb{R}_{\ge 0}\big[(x\le y)\implies\big(\Floor{x}\le\Floor{y}\big)\big] - monotonicity
- \forall x\in\mathbb{R}_{\ge 0}\exists\epsilon\in[0,1)\subseteq\mathbb{R}\big[x\eq\Floor{x}+\epsilon\big] - the characteristic property of the floor function
I believe that 3\implies 1 and 3\implies 2 might be possible, so these are perhaps in the wrong order. I just wanted to write down some notes before they get put into the massive stack of unfiled paper
This is a corollary to property 3 coupled with the definition (domain and co domain) of the floor function:
- \forall x\in\mathbb{R}_{\ge 0}\big[\Floor{x}\le x<\Floor{x}+1\big]
This statement is a critical part of finding Mdms and was used in:
- Mdm of a discrete distribution lemma
- Which at the time of writing (Alec (talk) 21:20, 21 January 2018 (UTC)) only exists as notes: Notes:Mdm of a discrete distribution lemma