Difference between revisions of "Pre-image sigma-algebra"

From Maths
Jump to: navigation, search
m (Added see-also)
m (Proof of claims: Linked to subpage in theorem box)
Line 7: Line 7:
 
==Proof of claims==
 
==Proof of claims==
 
{{Begin Inline Theorem}}
 
{{Begin Inline Theorem}}
'''Claim 1: ''' {{M|(X,\mathcal{A})}} is indeed a [[sigma-algebra|{{sigma|algebra}}]]
+
'''[[Pre-image sigma-algebra/Proof of claim: it is a sigma-algebra|Claim 1]]: ''' {{M|(X,\mathcal{A})}} is indeed a [[sigma-algebra|{{sigma|algebra}}]]
 
{{Begin Inline Proof}}
 
{{Begin Inline Proof}}
 
{{:Pre-image sigma-algebra/Proof of claim: it is a sigma-algebra}}
 
{{:Pre-image sigma-algebra/Proof of claim: it is a sigma-algebra}}
 
{{End Proof}}{{End Theorem}}
 
{{End Proof}}{{End Theorem}}
 +
 
==See also==
 
==See also==
 
* [[Trace sigma-algebra|Trace {{sigma|algebra}}]]
 
* [[Trace sigma-algebra|Trace {{sigma|algebra}}]]

Revision as of 14:04, 18 March 2016

Pre-image [ilmath]\sigma[/ilmath]-algebra
[math]\{f^{-1}(A')\ \vert\ A'\in\mathcal{A}'\}[/math]

is a [ilmath]\sigma[/ilmath]-algebra on [ilmath]X[/ilmath] given a [ilmath]\sigma[/ilmath]-algebra [ilmath](X',\mathcal{A}')[/ilmath] and a map [ilmath]f:X\rightarrow X'[/ilmath].

(Unknown grade)
This page is a stub
This page is a stub, so it contains little or minimal information and is on a to-do list for being expanded.The message provided is:
Add to sigma-algebra index, link to other pages, general expansion
This page is currently being refactored (along with many others)
Please note that this does not mean the content is unreliable. It just means the page doesn't conform to the style of the site (usually due to age) or a better way of presenting the information has been discovered.

Definition

Let [ilmath]\mathcal{A}'[/ilmath] be a [ilmath]\sigma[/ilmath]-algebra on [ilmath]X'[/ilmath] and let [ilmath]f:X\rightarrow X'[/ilmath] be a map. The pre-image [ilmath]\sigma[/ilmath]-algebra on [ilmath]X[/ilmath][1] is the [ilmath]\sigma[/ilmath]-algebra, [ilmath]\mathcal{A} [/ilmath] (on [ilmath]X[/ilmath]) given by:

  • [math]\mathcal{A}:=\left\{f^{-1}(A')\ \vert\ A'\in\mathcal{A}'\right\}[/math]

We can write this (for brevity) alternatively as:

Claim: [ilmath](X,\mathcal{A})[/ilmath] is indeed a [ilmath]\sigma[/ilmath]-algebra

Proof of claims

Claim 1: [ilmath](X,\mathcal{A})[/ilmath] is indeed a [ilmath]\sigma[/ilmath]-algebra



(Unknown grade)
This page requires one or more proofs to be filled in, it is on a to-do list for being expanded with them.
Please note that this does not mean the content is unreliable. Unless there are any caveats mentioned below the statement comes from a reliable source. As always, Warnings and limitations will be clearly shown and possibly highlighted if very important (see template:Caution et al).
The message provided is:
Should be pretty easy, it's just showing the definitions




See also

References

  1. Measures, Integrals and Martingales - René L. Schilling

OLD PAGE

Let [ilmath]f:X\rightarrow X'[/ilmath] and let [ilmath]\mathcal{A}'[/ilmath] be a [ilmath]\sigma[/ilmath]-algebra on [ilmath]X'[/ilmath], we can define a sigma algebra on [ilmath]X[/ilmath], called [ilmath]\mathcal{A} [/ilmath], by:

  • [ilmath]\mathcal{A}:=f^{-1}(\mathcal{A}'):=\left\{f^{-1}(A')\vert\ A'\in\mathcal{A}'\right\}[/ilmath]

TODO: Measures Integrals and Martingales - page 16