Mathjax bug
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Revision as of 16:39, 13 March 2015 by Alec (Talk | contribs) (Created page with "<pre> f(\sum^\infty_{n=1}b_n)= \begin{array} f(\sum^n_{i=1}a_i) \\ \sum^\infty_{n=1}f(b_n)=\sum^n_{i=1}f(a_i)+f(0)=\sum^n_{i=1}f(a_i) \end{array} </pre> produces: <math>f(\...")
f(\sum^\infty_{n=1}b_n)=
\begin{array}
f(\sum^n_{i=1}a_i) \\
\sum^\infty_{n=1}f(b_n)=\sum^n_{i=1}f(a_i)+f(0)=\sum^n_{i=1}f(a_i)
\end{array}
produces:
[math]f(\sum^\infty_{n=1}b_n)= \begin{array} f(\sum^n_{i=1}a_i) \\ \sum^\infty_{n=1}f(b_n)=\sum^n_{i=1}f(a_i)+f(0)=\sum^n_{i=1}f(a_i) \end{array}[/math]
f(\sum^\infty_{n=1}b_n)=
\begin{array}
fg(\sum^n_{i=1}a_i) \\
\sum^\infty_{n=1}f(b_n)=\sum^n_{i=1}f(a_i)+f(0)=\sum^n_{i=1}f(a_i)
\end{array}
produces:
[math]f(\sum^\infty_{n=1}b_n)= \begin{array} fg(\sum^n_{i=1}a_i) \\ \sum^\infty_{n=1}f(b_n)=\sum^n_{i=1}f(a_i)+f(0)=\sum^n_{i=1}f(a_i) \end{array}[/math]
