Characteristic property of the disjoint union topology/Proof
From Maths
Suppose f:∐α∈IXα→Y is continuous ⟹ ∀β∈I[f|X∗β:X∗β→Y is continuous]
Let β∈I be given.
- Let U∈K be given (so U is an open set in Y)
- By hypothesis, f−1(U)∈J (where J is the topology on ∐α∈IXα)
- This means ∀γ∈I∃V∈Jγ[f−1(U)∩iγ(Xγ)=V]
- Thus ∃V∈Jβ[f−1(U)∩iβ(Xβ)=V]
- But:
- f|−1X∗β(U)=f−1(U)∩X∗β Caution:This really ought to have its own proof
- So for V being the image of some open set under the canonical injection, iβ
Work required:
- Some sort of homeomorphism between (Xα,Jα) and the subspace X∗α:=iα(Xα) is needed