Difference between revisions of "A sequence consisting of the nth terms of the sequences in a Cauchy sequence of elements in any little-L space is itself a Cauchy sequence of complex numbers"
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** Notice that {{M|x:\eq(x^n_k)_{n\in\mathbb{N} } :\eq (x^1_k,x^2_k,\ldots,x^n_k,\ldots)}} - the {{M|k^\text{th} }} term of each element in {{M|x}} | ** Notice that {{M|x:\eq(x^n_k)_{n\in\mathbb{N} } :\eq (x^1_k,x^2_k,\ldots,x^n_k,\ldots)}} - the {{M|k^\text{th} }} term of each element in {{M|x}} | ||
==Proof== | ==Proof== | ||
− | {{Requires proof|grade= | + | {{Requires proof|grade=E|msg=I've just done it on paper, upload that! |
+ | <gallery> | ||
+ | File:CauchySequenceOfNthsTermsOfCauchySequenceInEllpProof.jpg|Proof on paper! | ||
+ | </gallery> | ||
+ | }} | ||
==References== | ==References== | ||
<references/> | <references/> | ||
{{Theorem Of|Functional Analysis|Analysis}} | {{Theorem Of|Functional Analysis|Analysis}} |
Latest revision as of 17:52, 18 March 2017
- This theorem is a precursor to the little-L spaces are complete
Contents
Statement
Let [ilmath]p\in[1,+\infty]\subseteq\overline{\mathbb{R} } [/ilmath] be given and consider the [ilmath]\ell^p[/ilmath] space accordingly. So elements in [ilmath]\ell^p[/ilmath] are [ilmath](x_n)_{n\in\mathbb{N} }\subseteq\mathbb{C} [/ilmath] such that certain properties hold.
Let [ilmath]\big((x_n^k)_{n\in\mathbb{N} }\big)_{k\in\mathbb{N} } \subseteq\ell^p[/ilmath] be a Cauchy sequence
- i.e. [ilmath]\big((x^1_n)_{n\in\mathbb{N} },(x^2_n)_{n\in\mathbb{N} },\ldots,(x^k_n)_{n\in\mathbb{N} },\ldots\big)\subseteq\ell^p[/ilmath] is a Cauchy sequence
Then we claim[1]:
- for all [ilmath]k\in\mathbb{N} [/ilmath] that [ilmath]x:\eq(x^n_k)_{n\in\mathbb{N} }\subseteq\mathbb{C} [/ilmath] is itself a Cauchy sequence
- Notice that [ilmath]x:\eq(x^n_k)_{n\in\mathbb{N} } :\eq (x^1_k,x^2_k,\ldots,x^n_k,\ldots)[/ilmath] - the [ilmath]k^\text{th} [/ilmath] term of each element in [ilmath]x[/ilmath]
Proof
Grade: E
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References