Geometric distribution

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Geometric Distribution
XGeo(p)

for p the probability of each trials' success

X=k means that the first failure occurred on the kth trial, kN1
Definition
Defined over X may take values in N1={1,2,}
p.m.f P[X=k]:=(1p)k1p
c.d.f / c.m.f[Note 1] P[Xk]=1(1p)k
cor: P[Xk]=(1p)k1
Properties
Expectation: E[X]=1p
Variance:
TODO: Unknown
[Note 2]

Notes

during proof of P[Xk] the result is obtained using a geometric series, however one has to align the sequences (not adjust the sum to start at zero, unless you adjust the Sn formula too!)

Check the variance, I did part the proof, checked the MEI formula book and moved on, I didn't confirm interpretation.


Make a note that my Casio calculator uses 1p as the parameter, giving P[X=k]:=(1p)k1p along with the interpretation that allows 0

Definition

References

Notes

  1. <cite_references_link_accessibility_label> Do we make this distinction for cumulative distributions?
  2. <cite_references_link_accessibility_label> Due to different conventions on the definition of geometric (for example X:=X1 for my X and another's XGeo(p)) or even differing by using 1p in place of p in the X and X just mentioned - I cannot be sure without working it out that it's 1pp2 - I record this value only for a record of what was once there with the correct expectation - DO NOT USE THIS EXPRESSION