Difference between revisions of "Derivative (analysis)"
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− | There are 2 kinds of derivative, a ''[[strong derivative]]'' ({{AKA}} the [[Frécet derivative]], [[total derivative]]<ref group="reqref">Requires reference</ref>) one and a ''[[ | + | There are 2 kinds of derivative, a ''[[strong derivative]]'' ({{AKA}} the [[Frécet derivative]], [[total derivative]]<ref group="reqref">Requires reference</ref>) one and a ''[[directional derivative]]'' one ({{AKA}} the [[Gateaux derivative]], [[weak derivative]]) |
===[[Strong derivative]]=== | ===[[Strong derivative]]=== | ||
− | {{ | + | {{Todo|List of conditions}} |
{{Todo|Weak derivative}} | {{Todo|Weak derivative}} | ||
Revision as of 10:44, 11 March 2016
Contents
Definition
There are 2 kinds of derivative, a strong derivative (AKA the Frécet derivative, total derivative[reqref 1]) one and a directional derivative one (AKA the Gateaux derivative, weak derivative)
Strong derivative
TODO: List of conditions
TODO: Weak derivative
Required references
- ↑ Requires reference
References
OLD PAGE
Note to self: don't forget to mention the [ilmath]h[/ilmath] or [ilmath]x-x_0[/ilmath] thing doesn't matter
Definition
- Note: there are 2 definitions of differentiability, I will state them both here, then prove them equivalent.
Let [ilmath]U[/ilmath] be an open set of a Banach space [ilmath]X[/ilmath], let [ilmath]Y[/ilmath] be another Banach space.
- Let [ilmath]f:X\rightarrow Y[/ilmath] be a given map
- Let [ilmath]x_0\in X[/ilmath] be a point.
Definition 1
We say that [ilmath]f[/ilmath] is differentiable at a point [ilmath]x_0\in X[/ilmath] if[1][2]:
- there exists a continuous linear map, [ilmath]L_{x_0}\in L(X,Y)[/ilmath] such that:
- [ilmath]T(x_0+h)-T(x_0)=L_{x_0}(h)+r(x_0,h)[/ilmath] where [math]\ \lim_{h\rightarrow 0}\left(\frac{\Vert r(x_0,h)\Vert}{\Vert h\Vert}\right)=0[/math]
Definition 2
We say that [ilmath]f[/ilmath] is differentiable at a point [ilmath]x_0\in X[/ilmath] if[2]:
- there exists a continuous linear map, [ilmath]L_{x_0}\in L(X,Y)[/ilmath] such that:
- [math]\lim_{h\rightarrow 0}\left(\frac{f(x_0+h)-f(x_0)-L_{x_0}(h)}{\Vert h\Vert}\right)=0[/math]
Hybrid definition
These naturally lead to: We say that [ilmath]f[/ilmath] is differentiable at a point [ilmath]x_0\in X[/ilmath] if:
- there exists a continuous linear map, [ilmath]L_{x_0}\in L(X,Y)[/ilmath] such that:
- [math]\lim_{h\rightarrow 0}\left(\frac{\Vert f(x_0+h)-f(x_0)-L_{x_0}(h)\Vert}{\Vert h\Vert}\right)=0[/math]
Extra workings for proof
- there exists a continuous linear map, [ilmath]L_{x_0}\in L(X,Y)[/ilmath] such that:
- [ilmath]T(x_0+h)-T(x_0)=L_{x_0}(h)+r(x_0,h)[/ilmath] where [math]\ \lim_{h\rightarrow 0}\left(\frac{\Vert r(x_0,h)\Vert}{\Vert h\Vert}\right)=0[/math]
- This can be interpreted as [math]\ \exists L_{x_0}\in L(X,Y)\left[\lim_{h\rightarrow 0}\left(\frac{\Vert r(x_0,h)\Vert}{\Vert h\Vert}\right)=0\implies T(x_0+h)-T(x_0)=L_{x_0}(h)+r(x_0,h)\right][/math]
- Which is
- [math]\exists L_{x_0}\in L(X,Y)\forall\epsilon>0\exists\delta>0\forall h\in X\left[0<\Vert h-x\Vert<\delta\implies\frac{\Vert r(x_0,h)\Vert}{\Vert h\Vert}<\epsilon\implies T(x_0+h)-T(x_0)=L_{x_0}(h)+r(x_0,h)\right][/math]
- Does this make sense though? We need [ilmath]r(x_0,\cdot)[/ilmath] to be given, surely a form with [ilmath]r(x_0,h)=T(x_0+h)-T(x_0)-L_{x_0}(h)[/ilmath] in the numerator would make more sense? No of course not.
- [math]\exists L_{x_0}\in L(X,Y)\forall\epsilon>0\exists\delta>0\forall h\in X\left[0<\Vert h-x\Vert<\delta\implies\frac{\Vert r(x_0,h)\Vert}{\Vert h\Vert}<\epsilon\implies T(x_0+h)-T(x_0)=L_{x_0}(h)+r(x_0,h)\right][/math]
- Which is