Difference between revisions of "Smooth function"

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==Definition==
 
==Definition==
A '''smooth function''' on a [[Smooth manifold|smooth {{n|manifold}}]], {{M|(M,\mathcal{A})}}, is a function<ref>Introduction to smooth manifolds - John M Lee - Second Edition</ref> {{M|f:M\rightarrow\mathbb{R}^k}} that satisfies:
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A '''smooth function''' on a [[Smooth manifold|smooth {{n|manifold}}]], {{M|(M,\mathcal{A})}}, is a function<ref>Introduction to smooth manifolds - John M Lee - Second Edition</ref> {{M|f:M\rightarrow\mathbb{R} }} that satisfies:
  
{{M|\forall p\in M\ \exists\ (U,\varphi)\in\mathcal{A} }} such that {{M|f\circ\varphi^{-1}\subseteq\mathbb{R}^n\rightarrow\mathbb{R}^k }} is [[Smooth|smooth]] in the usual sense, of having continuous partial derivatives of all orders.  
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*{{M|\forall p\in M\ \exists\ (U,\varphi)\in\mathcal{A}[p\in U\wedge f\circ\varphi^{-1}:\varphi(U)\subseteq\mathbb{R}^n\rightarrow\mathbb{R}\in C^\infty]}}
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** That is to say {{M|f\circ\varphi^{-1} }} is [[Smooth|smooth]] in the usual sense - of having continuous partial derivatives of all orders.  
  
Any smoothly compatible map (so all in the atlas of the smooth manifold) will have a smooth transition function, by composition, the result will be smooth, so {{M|f}} is still smooth.
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{{Begin Theorem}}
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Theorem: Any other chart in {{M|(M,\mathcal{A})}} will also satisfy the definition of {{M|f}} being smooth
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{{Begin Proof}}
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Let {{M|(M,\mathcal{A})}} be a given [[Smooth manifold|smooth manifold]]
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Let {{M|(U,\varphi)}} be a chart, on which {{M|f\circ\varphi^{-1}:\varphi(U)\rightarrow\mathbb{R} }} is [[Smooth|smooth]]
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We wish to show any [[Smoothly compatible charts|smoothly compatible chart]] with {{M|(U,\varphi)}} will support the definition of {{M|f}} being smooth.
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That is to say all other charts in the [[Smooth atlas|smooth atlas]] {{M|\mathcal{A} }}
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'''Proof:'''
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: Let {{M|(V,\psi)}} be any chart in {{M|\mathcal{A} }} be given.
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:: Then {{M|(U,\varphi)}} and {{M|(V,\psi)}} are smoothly compatible
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:: this means that either:
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::* {{M|U\cap V}} is empty - in which case there is nothing to show OR
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::* {{M|\varphi\circ\psi^{-1}:\psi(U\cap V)\rightarrow\varphi(U\cap V)}} is a [[Diffeomorphism|diffeomorphism]]
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::: We can compose this with {{M|f\circ\varphi^{-1}:\varphi(U)\rightarrow\mathbb{R} }} as follows
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:::: {{M|(f\circ\varphi^{-1})\circ(\varphi\circ\psi^{-1}):\psi(U\cap V)\rightarrow\mathbb{R} }} which is [[Smooth|smooth]] as it is a composition of smooth functions
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:::: {{M|1==f\circ\varphi^{-1}\circ\varphi\circ\psi^{-1}:\psi(U\cap V)\rightarrow\mathbb{R} }}
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:::: {{M|1==f\circ\psi^{-1}:\psi(U\cap V)\rightarrow\mathbb{R} }} - which we know to be smooth as it is ''equal to'' {{M|(f\circ\varphi^{-1})\circ(\varphi\circ\psi^{-1}):\psi(U\cap V)\rightarrow\mathbb{R} }} - which as we've said is smooth
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 +
QED
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{{End Proof}}
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{{End Theorem}}
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===Extending to vectors===
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 +
Note that given an {{M|f:M\rightarrow\mathbb{R}^k}} this is actually just a set of functions, {{M|f_1,\cdots,f_k}} where {{M|f_i:M\rightarrow\mathbb{R} }} and {{M|1=f(p)=(f_1(p),\cdots,f_k(p))}}
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 +
 
 +
We can define {{M|f:M\rightarrow\mathbb{R}^k}} as being smooth {{M|1=\iff\forall i=1,\cdots k}} we have {{M|f_i:M\rightarrow\mathbb{R} }} being smooth
 +
 
 +
==Notations==
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===The set of all smooth functions===
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Without knowledge of [[Smooth manifold|smooth manifolds]] we may already define {{M|C^\infty(\mathbb{R}^n)}} - the set of all functions with continuous partial derivatives of all orders.
 +
 
 +
However with this definition of a smooth function we may go further:
 +
===The set of all smooth functions on a manifold===
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Given a [[Smooth manifold|smooth {{n|manifold}}]], {{M|M}}, we now know what it means for a function to be smooth on it, so:
 +
 
 +
Let <math>f\in C^\infty(M)\iff f:M\rightarrow\mathbb{R}</math> is smooth
  
 
==See also==
 
==See also==
 +
* [[Smooth map]]
 
* [[Smooth manifold]]
 
* [[Smooth manifold]]
 
* [[Smoothly compatible charts]]
 
* [[Smoothly compatible charts]]

Latest revision as of 16:16, 14 April 2015

Definition

A smooth function on a smooth n-manifold, (M,A), is a function[1] f:MR that satisfies:

  • pM  (U,φ)A[pUfφ1:φ(U)RnRC]
    • That is to say fφ1 is smooth in the usual sense - of having continuous partial derivatives of all orders.
[Expand]

Theorem: Any other chart in (M,A) will also satisfy the definition of f being smooth


Extending to vectors

Note that given an f:MRk this is actually just a set of functions, f1,,fk where fi:MR and f(p)=(f1(p),,fk(p))


We can define f:MRk as being smooth i=1,k we have fi:MR being smooth

Notations

The set of all smooth functions

Without knowledge of smooth manifolds we may already define C(Rn) - the set of all functions with continuous partial derivatives of all orders.

However with this definition of a smooth function we may go further:

The set of all smooth functions on a manifold

Given a smooth n-manifold, M, we now know what it means for a function to be smooth on it, so:

Let fC(M)f:MR

is smooth

See also

References

  1. Jump up Introduction to smooth manifolds - John M Lee - Second Edition