Difference between revisions of "Pasting lemma"

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(Created page with "{{Stub page|grade=A*|msg=Create the closed pasting lemma and open pasting lemma pages. Do the proof, see page 58.9 in Lee's top manifolds if stuck, shouldn't be stuck}...")
 
m (Statement: linking "restriction")
 
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* such that {{M|1=\forall \alpha,\beta\in I\forall x\in A_\alpha\cap A_\beta[f_\alpha(x)=f_\beta(x)]}}
 
* such that {{M|1=\forall \alpha,\beta\in I\forall x\in A_\alpha\cap A_\beta[f_\alpha(x)=f_\beta(x)]}}
 
then{{rITTMJML}}:
 
then{{rITTMJML}}:
* there exists a unique continuous map, {{M|f:X\rightarrow Y}}, such that {{M|f}}'s restriction to each {{M|A_\alpha}} is {{M|f_\alpha}}
+
* there exists a unique continuous map, {{M|f:X\rightarrow Y}}, such that {{M|f}}'s {{link|restriction|function}} to each {{M|A_\alpha}} is {{M|f_\alpha}}
 +
 
 
==Proof==
 
==Proof==
 
{{Requires proof|grade=A|msg=Do this, but remember it's the union of two other lemmas, so you can just write "by this, that" twice}}
 
{{Requires proof|grade=A|msg=Do this, but remember it's the union of two other lemmas, so you can just write "by this, that" twice}}

Latest revision as of 07:07, 14 October 2016

Stub grade: A*
This page is a stub
This page is a stub, so it contains little or minimal information and is on a to-do list for being expanded.The message provided is:
Create the closed pasting lemma and open pasting lemma pages. Do the proof, see page 58.9 in Lee's top manifolds if stuck, shouldn't be stuck
The closed pasting lemma and open pasting lemma are proved separately, this just unites the two.

Statement

Let [ilmath](X,\mathcal{ J })[/ilmath] and [ilmath](Y,\mathcal{ K })[/ilmath] be topological spaces, let [ilmath]\{A_\alpha\}_{\alpha\in I} [/ilmath] be either:

  1. An arbitrary open cover of [ilmath]X[/ilmath], or
  2. A finite closed cover of [ilmath]X[/ilmath]

and let [ilmath]\{f_\alpha:A_\alpha\rightarrow Y\}_{\alpha\in I} [/ilmath] be a family of continuous maps that agree where they overlap, formally:

  • such that [ilmath]\forall \alpha,\beta\in I\forall x\in A_\alpha\cap A_\beta[f_\alpha(x)=f_\beta(x)][/ilmath]

then[1]:

  • there exists a unique continuous map, [ilmath]f:X\rightarrow Y[/ilmath], such that [ilmath]f[/ilmath]'s restriction to each [ilmath]A_\alpha[/ilmath] is [ilmath]f_\alpha[/ilmath]

Proof

Grade: A
This page requires one or more proofs to be filled in, it is on a to-do list for being expanded with them.
Please note that this does not mean the content is unreliable. Unless there are any caveats mentioned below the statement comes from a reliable source. As always, Warnings and limitations will be clearly shown and possibly highlighted if very important (see template:Caution et al).
The message provided is:
Do this, but remember it's the union of two other lemmas, so you can just write "by this, that" twice

References

  1. Introduction to Topological Manifolds - John M. Lee