Difference between revisions of "Passing to the quotient (topology)/Statement"

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==Statement==
 
==Statement==
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That means that:  
 
That means that:  
* {{M|1=\pi(x)=\pi(y)\implies f(x)=f(y)}} - exactly as in [[quotient (function)]]
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* {{M|1=\forall x,y\in X[\pi(x)=\pi(y)\implies f(x)=f(y)]}} - as mentioned in [[passing to the quotient (function)|passing-to-the-quotient for functions]], or
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* {{M|1=\forall x,y\in X[f(x)\ne f(y)\implies \pi(x)\ne\pi(y)]}}, also mentioned
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* See :- [[Equivalent conditions to being constant on the fibres of a map]] for details
 
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--></ref> then:
 
--></ref> then:
 
* there exists a unique continuous map, {{M|\bar{f}:\frac{X}{\sim}\rightarrow Y}} such that {{M|1=f=\overline{f}\circ\pi }}
 
* there exists a unique continuous map, {{M|\bar{f}:\frac{X}{\sim}\rightarrow Y}} such that {{M|1=f=\overline{f}\circ\pi }}
We may then say {{M|f}} ''descends to the quotient'' or ''passes to the quotient''<div style="clear:both;"></div>
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We may then say {{M|f}} ''descends to the quotient'' or ''passes to the quotient''
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: '''Note: ''' this is an instance of ''[[passing to the quotient (function)|passing-to-the-quotient for functions]]''<div style="clear:both;"></div>
 
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==Notes==
 
==Notes==

Latest revision as of 20:23, 11 October 2016


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Statement

f descends to the quotient

Suppose that (X,J) is a topological space and is an equivalence relation, let (X,Q) be the resulting quotient topology and π:XX the resulting quotient map, then:

  • Let (Y,K) be any topological space and let f:XY be a continuous map that is constant on the fibres of π[Note 1] then:
  • there exists a unique continuous map, ˉf:XY such that f=¯fπ

We may then say f descends to the quotient or passes to the quotient

Note: this is an instance of passing-to-the-quotient for functions

Notes

  1. Jump up That means that:

References