Difference between revisions of "Algebra of sets"
(every Algebra of sets is an Algebra of sets??) |
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+ | {{Refactor notice}} | ||
+ | {{Stub page}} | ||
+ | {{Requires references}} | ||
+ | {{:Algebra of sets/Infobox}} | ||
+ | : '''Note: ''' Every ''algebra of sets'' is a ''[[ring of sets]]'' (see below) | ||
+ | __TOC__ | ||
+ | ==Definition== | ||
+ | An ''algebra of sets'' is a collection of sets, {{M|\mathcal{A} }} such that{{rMTH}}: | ||
+ | * {{M|1=\forall A\in\mathcal{A}[A^C\in\mathcal{A}]}}<ref group="Note">Recall {{M|1=A^C:=X-A}} - the [[complement]] of {{M|A}} in {{M|X}}</ref> | ||
+ | ** In words: For all {{M|A}} in {{M|\mathcal{A} }} the [[complement]] of {{M|A}} (with respect to {{M|X}}) is also in {{M|\mathcal{A} }} | ||
+ | * {{M|1=\forall A,B\in\mathcal{A}[A\cup B\in\mathcal{A}]}} | ||
+ | ** In words: For all {{M|A}} and {{M|B}} in {{M|\mathcal{A} }} their [[union]] is also in {{M|\mathcal{A} }} | ||
+ | '''[[Algebra of sets#Proof of claims|Claim 1]]: ''' Every ''algebra of sets'' is also a ''[[ring of sets]]'' | ||
+ | ==Immediate properties== | ||
+ | {{Todo|Do this as a list of inline theorem boxes}} | ||
+ | * {{M|\mathcal{A} }} is {{M|\setminus}}-closed | ||
+ | * {{M|\emptyset\in\mathcal{A} }} | ||
+ | * {{M|X\in\mathcal{A} }} | ||
+ | * {{M|\mathcal{A} }} is {{M|\cap}}-closed | ||
+ | ==Proof of claims== | ||
+ | {{Begin Inline Theorem}} | ||
+ | '''Claim 1: ''' Every ''algebra of sets'' is also a ''[[ring of sets]]'' | ||
+ | {{Begin Inline Proof}} | ||
+ | This is trivial. In order to show {{M|\mathcal{A} }} is a [[ring of sets]] we require two properties: | ||
+ | # {{M|\forall A,B\in\mathcal{A}[A\cup B\in\mathcal{A}]}} - this is clearly satisfied by definition of an algebra of sets | ||
+ | # {{M|\forall A,B\in\mathcal{A}[A-B\in\mathcal{A}]}} - that is {{M|\mathcal{A} }} must be {{M|\setminus}}-closed | ||
+ | #* But we've already shown this in the [[Algebra of sets#Immediate properties|''immediate properties'']] section above! | ||
+ | This completes the proof | ||
+ | {{End Proof}}{{End Theorem}} | ||
+ | ==See also== | ||
+ | * [[Types of set algebras]] | ||
+ | * [[ring of sets]] | ||
+ | ** [[sigma-ring|{{sigma|ring}}]] | ||
+ | * [[sigma-algebra|{{sigma|algebra}}]] | ||
+ | ==Notes== | ||
+ | <references group="Note"/> | ||
+ | ==References== | ||
+ | <references/> | ||
+ | {{Measure theory navbox|plain}} | ||
+ | {{Definition|Measure Theory}} | ||
+ | |||
+ | =OLD PAGE= | ||
An Algebra of sets is sometimes called a '''Boolean algebra''' | An Algebra of sets is sometimes called a '''Boolean algebra''' | ||
Latest revision as of 18:43, 1 April 2016
Algebra of sets | |
[ilmath]\mathcal{A}\subseteq\mathcal{P}(X)[/ilmath] For an algebra of sets, [ilmath]\mathcal{A} [/ilmath] on [ilmath]X[/ilmath] | |
Defining properties: | |
---|---|
1) | [ilmath]\forall A\in\mathcal{A}[A^C\in\mathcal{A}][/ilmath] |
2) | [ilmath]\forall A,B\in\mathcal{A}[A\cup B\in\mathcal{A} ][/ilmath] |
- Note: Every algebra of sets is a ring of sets (see below)
Contents
Definition
An algebra of sets is a collection of sets, [ilmath]\mathcal{A} [/ilmath] such that[1]:
- [ilmath]\forall A\in\mathcal{A}[A^C\in\mathcal{A}][/ilmath][Note 1]
- In words: For all [ilmath]A[/ilmath] in [ilmath]\mathcal{A} [/ilmath] the complement of [ilmath]A[/ilmath] (with respect to [ilmath]X[/ilmath]) is also in [ilmath]\mathcal{A} [/ilmath]
- [ilmath]\forall A,B\in\mathcal{A}[A\cup B\in\mathcal{A}][/ilmath]
- In words: For all [ilmath]A[/ilmath] and [ilmath]B[/ilmath] in [ilmath]\mathcal{A} [/ilmath] their union is also in [ilmath]\mathcal{A} [/ilmath]
Claim 1: Every algebra of sets is also a ring of sets
Immediate properties
TODO: Do this as a list of inline theorem boxes
- [ilmath]\mathcal{A} [/ilmath] is [ilmath]\setminus[/ilmath]-closed
- [ilmath]\emptyset\in\mathcal{A} [/ilmath]
- [ilmath]X\in\mathcal{A} [/ilmath]
- [ilmath]\mathcal{A} [/ilmath] is [ilmath]\cap[/ilmath]-closed
Proof of claims
Claim 1: Every algebra of sets is also a ring of sets
This is trivial. In order to show [ilmath]\mathcal{A} [/ilmath] is a ring of sets we require two properties:
- [ilmath]\forall A,B\in\mathcal{A}[A\cup B\in\mathcal{A}][/ilmath] - this is clearly satisfied by definition of an algebra of sets
- [ilmath]\forall A,B\in\mathcal{A}[A-B\in\mathcal{A}][/ilmath] - that is [ilmath]\mathcal{A} [/ilmath] must be [ilmath]\setminus[/ilmath]-closed
- But we've already shown this in the immediate properties section above!
This completes the proof
See also
Notes
- ↑ Recall [ilmath]A^C:=X-A[/ilmath] - the complement of [ilmath]A[/ilmath] in [ilmath]X[/ilmath]
References
|
OLD PAGE
An Algebra of sets is sometimes called a Boolean algebra
We will show later that every Algebra of sets is an Algebra of sets
TODO: what could this mean?
Definition
An class [ilmath]R[/ilmath] of sets is an Algebra of sets if[1]:
- [math][A\in R\wedge B\in R]\implies A\cup B\in R[/math]
- [math]A\in R\implies A^c\in R[/math]
So an Algebra of sets is just a Ring of sets containing the entire set it is a set of subsets of!
Every Algebra is also a Ring
Since for [math]A\in R[/math] and [math]B\in R[/math] we have:
[math]A-B=A\cap B' = (A'\cup B)'[/math] we see that being closed under Complement and Union means it is closed under Set subtraction
Thus it is a Ring of sets
See also
References
- ↑ p21 - Halmos - Measure Theory - Graduate Texts In Mathematics - Springer - #18