Difference between revisions of "Norm"
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* <math>\|x\|\ge 0\text{ and }\|x\|=0\iff x=0</math> so only 3 requirements will be stated. | * <math>\|x\|\ge 0\text{ and }\|x\|=0\iff x=0</math> so only 3 requirements will be stated. | ||
I don't like this (inline with the [[Doctrine of monotonic definition]]) | I don't like this (inline with the [[Doctrine of monotonic definition]]) | ||
− | + | ==Properties== | |
+ | * [[The norm of a space is a uniformly continuous map with respect to the topology it induces]] - {{M|\Vert\cdot\Vert:X\rightarrow\mathbb{R} }} is a [[uniformly continuous]] map. | ||
==Terminology== | ==Terminology== | ||
Such a vector space equipped with such a function is called a [[Normed space|normed space]]<ref name="APIKM"/> | Such a vector space equipped with such a function is called a [[Normed space|normed space]]<ref name="APIKM"/> | ||
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* <math>d(x,y):=\|x-y\|</math> | * <math>d(x,y):=\|x-y\|</math> | ||
(See [[Subtypes of topological spaces]] for more information, this relationship is very important in [[Functional analysis]]) | (See [[Subtypes of topological spaces]] for more information, this relationship is very important in [[Functional analysis]]) | ||
− | {{Todo| | + | {{Todo|Move to its own page and do a proof (trivial)}} |
+ | |||
==Weaker and stronger norms== | ==Weaker and stronger norms== | ||
Given a norm <math>\|\cdot\|_1</math> and another <math>\|\cdot\|_2</math> we say: | Given a norm <math>\|\cdot\|_1</math> and another <math>\|\cdot\|_2</math> we say: | ||
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==References== | ==References== | ||
<references/> | <references/> | ||
− | + | {{Normed and Banach spaces navbox}} | |
+ | {{Metric spaces navbox}} | ||
+ | {{Topology navbox}} | ||
{{Definition|Linear Algebra|Topology|Metric Space|Functional Analysis}} | {{Definition|Linear Algebra|Topology|Metric Space|Functional Analysis}} | ||
+ | [[Category:Exemplary pages]] | ||
+ | [[Category:First-year friendly]] |
Latest revision as of 20:33, 9 April 2017
Norm | |
[ilmath]\Vert\cdot\Vert:V\rightarrow\mathbb{R}_{\ge 0} [/ilmath] Where [ilmath]V[/ilmath] is a vector space over the field [ilmath]\mathbb{R} [/ilmath] or [ilmath]\mathbb{C} [/ilmath] | |
relation to other topological spaces | |
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is a | |
contains all | |
Related objects | |
Induced metric |
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Induced by inner product |
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Contents
Definition
A norm on a vector space [ilmath](V,F)[/ilmath] (where [ilmath]F[/ilmath] is either [ilmath]\mathbb{R} [/ilmath] or [ilmath]\mathbb{C} [/ilmath]) is a function [math]\|\cdot\|:V\rightarrow\mathbb{R}[/math] such that[1][2][3][4]See warning notes:[Note 1][Note 2]:
- [math]\forall x\in V\ \|x\|\ge 0[/math]
- [math]\|x\|=0\iff x=0[/math]
- [math]\forall \lambda\in F, x\in V\ \|\lambda x\|=|\lambda|\|x\|[/math] where [math]|\cdot|[/math] denotes absolute value
- [math]\forall x,y\in V\ \|x+y\|\le\|x\|+\|y\|[/math] - a form of the triangle inequality
Often parts 1 and 2 are combined into the statement:
- [math]\|x\|\ge 0\text{ and }\|x\|=0\iff x=0[/math] so only 3 requirements will be stated.
I don't like this (inline with the Doctrine of monotonic definition)
Properties
- The norm of a space is a uniformly continuous map with respect to the topology it induces - [ilmath]\Vert\cdot\Vert:X\rightarrow\mathbb{R} [/ilmath] is a uniformly continuous map.
Terminology
Such a vector space equipped with such a function is called a normed space[1]
Relation to various subtypes of topological spaces
The reader should note that:
- Every inner product induces a norm and
- Every norm induces a metric
These are outlined below
Relation to inner product
Every inner product [ilmath]\langle\cdot,\cdot\rangle:V\times V\rightarrow(\mathbb{R}\text{ or }\mathbb{C})[/ilmath] induces a norm given by:
- [ilmath]\Vert x\Vert:=\sqrt{\langle x,x\rangle}[/ilmath]
TODO: see inner product (norm induced by) for more details, on that page is a proof that [ilmath]\langle x,x\rangle\ge 0[/ilmath], this needs its own page with a proof.
Metric induced by a norm
To get a metric space from a norm simply define[2][1]:
- [math]d(x,y):=\|x-y\|[/math]
(See Subtypes of topological spaces for more information, this relationship is very important in Functional analysis)
TODO: Move to its own page and do a proof (trivial)
Weaker and stronger norms
Given a norm [math]\|\cdot\|_1[/math] and another [math]\|\cdot\|_2[/math] we say:
- [math]\|\cdot\|_1[/math] is weaker than [math]\|\cdot\|_2[/math] if [math]\exists C> 0\forall x\in V[/math] such that [math]\|x\|_1\le C\|x\|_2[/math]
- [math]\|\cdot\|_2[/math] is stronger than [math]\|\cdot\|_1[/math] in this case
Equivalence of norms
Given two norms [math]\|\cdot\|_1[/math] and [math]\|\cdot\|_2[/math] on a vector space [ilmath]V[/ilmath] we say they are equivalent if:
[math]\exists c,C\in\mathbb{R}\text{ with }c,C>0\ \forall x\in V:\ c\|x\|_1\le\|x\|_2\le C\|x\|_1[/math]
Theorem: This is an Equivalence relation - so we may write this as [math]\|\cdot\|_1\sim\|\cdot\|_2[/math]
TODO: proof
Note also that if [math]\|\cdot\|_1[/math] is both weaker and stronger than [math]\|\cdot\|_2[/math] they are equivalent
Examples
- Any two norms on [math]\mathbb{R}^n[/math] are equivalent
- The norms [math]\|\cdot\|_{L^1}[/math] and [math]\|\cdot\|_\infty[/math] on [math]\mathcal{C}([0,1],\mathbb{R})[/math] are not equivalent.
Common norms
Name | Norm | Notes |
---|---|---|
Norms on [math]\mathbb{R}^n[/math] | ||
1-norm | [math]\|x\|_1=\sum^n_{i=1}|x_i|[/math] | it's just a special case of the p-norm. |
2-norm | [math]\|x\|_2=\sqrt{\sum^n_{i=1}x_i^2}[/math] | Also known as the Euclidean norm - it's just a special case of the p-norm. |
p-norm | [math]\|x\|_p=\left(\sum^n_{i=1}|x_i|^p\right)^\frac{1}{p}[/math] | (I use this notation because it can be easy to forget the [math]p[/math] in [math]\sqrt[p]{}[/math]) |
[math]\infty-[/math]norm | [math]\|x\|_\infty=\sup(\{x_i\}_{i=1}^n)[/math] | Also called sup-norm |
Norms on [math]\mathcal{C}([0,1],\mathbb{R})[/math] | ||
[math]\|\cdot\|_{L^p}[/math] | [math]\|f\|_{L^p}=\left(\int^1_0|f(x)|^pdx\right)^\frac{1}{p}[/math] | NOTE be careful extending to interval [math][a,b][/math] as proof it is a norm relies on having a unit measure |
[math]\infty-[/math]norm | [math]\|f\|_\infty=\sup_{x\in[0,1]}(|f(x)|)[/math] | Following the same spirit as the [math]\infty-[/math]norm on [math]\mathbb{R}^n[/math] |
[math]\|\cdot\|_{C^k}[/math] | [math]\|f\|_{C^k}=\sum^k_{i=1}\sup_{x\in[0,1]}(|f^{(i)}|)[/math] | here [math]f^{(k)}[/math] denotes the [math]k^\text{th}[/math] derivative. |
Induced norms | ||
Pullback norm | [math]\|\cdot\|_U[/math] | For a linear isomorphism [math]L:U\rightarrow V[/math] where V is a normed vector space |
Examples
Notes
- ↑ A lot of books, including the brilliant Analysis - Part 1: Elements - Krzysztof Maurin referenced here state explicitly that it is possible for [ilmath]\Vert\cdot,\cdot\Vert:V\rightarrow\mathbb{C} [/ilmath] they are wrong. I assure you that it is [ilmath]\Vert\cdot\Vert:V\rightarrow\mathbb{R}_{\ge 0} [/ilmath]. Other than this the references are valid, note that this is 'obvious' as if the image of [ilmath]\Vert\cdot\Vert[/ilmath] could be in [ilmath]\mathbb{C} [/ilmath] then the [ilmath]\Vert x\Vert\ge 0[/ilmath] would make no sense. What ordering would you use? The canonical ordering used for the product of 2 spaces ([ilmath]\mathbb{R}\times\mathbb{R} [/ilmath] in this case) is the Lexicographic ordering which would put [ilmath]1+1j\le 1+1000j[/ilmath]!
- ↑ The other mistake books make is saying explicitly that the field of a vector space needs to be [ilmath]\mathbb{R} [/ilmath], it may commonly be [ilmath]\mathbb{R} [/ilmath] but it does not need to be [ilmath]\mathbb{R} [/ilmath]
References
- ↑ 1.0 1.1 1.2 Analysis - Part 1: Elements - Krzysztof Maurin
- ↑ 2.0 2.1 Functional Analysis - George Bachman and Lawrence Narici
- ↑ Functional Analysis - A Gentle Introduction - Volume 1, by Dzung Minh Ha
- ↑ Real and Abstract Analysis - Edwin Hewitt & Karl Stromberg
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