Difference between revisions of "Quotient topology"

Revision as of 09:22, 7 April 2015

Quotient map

Let $(X,\mathcal{J})$ and $(Y,\mathcal{K})$ be topological spaces and let $p:X\rightarrow Y$ be a surjective map.

$p$ is a quotient map^[1] if we have $$U\in\mathcal{K}\iff p^{-1}(U)\in\mathcal{J}$$

Notes

Stronger than continuity

If we had $\mathcal{K}=\{\emptyset,Y\}$ then $p$ is automatically continuous (as it is surjective), the point is that $\mathcal{K}$ is the largest topology we can define on $Y$ such that $p$ is continuous

See Motivation for quotient topology for a discussion on where this goes.

Definition

If $$(X,\mathcal{J})$$ is a topological space, $$A$$ is a set, and $$p:(X,\mathcal{J})\rightarrow A$$ is a surjective map then there exists exactly one topology $$\mathcal{J}_Q$$ relative to which $$p$$ is a quotient map. This is the quotient topology induced by $$p$$

TODO: Munkres page 138

References

1. Jump up ↑ Topology - Second Edition - James R Munkres