Difference between revisions of "Quotient topology"
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− | {{ | + | ==Definition== |
+ | There are a few definitions of the quotient topology however they do not conflict. This page might change shape while things are put in place | ||
+ | ===[[Quotient topology/Equivalence relation definition|Quotient topology via an equivalence-relation definition]]=== | ||
+ | {{:Quotient topology/Equivalence relation definition}} | ||
+ | ===[[Quotient topology/Mapping to a set definition|Quotient topology via a mapping to a set definition]]=== | ||
+ | {{:Quotient topology/Mapping to a set definition}} | ||
+ | : '''Claim 1: ''' these definitions are equivalent | ||
+ | ===[[Universal property of the quotient topology]]=== | ||
+ | {{:Universal property of the quotient topology/Statement}} | ||
+ | ==Proof of claims== | ||
+ | ==Notes== | ||
+ | <references group="Note"/> | ||
+ | ==References== | ||
+ | <references/> | ||
+ | {{Topology navbox|plain}} | ||
+ | {{Definition|Topology}} | ||
+ | =OLD PAGE= | ||
+ | '''Note:''' [[Motivation for quotient topology]] may be useful | ||
==Definition of the Quotient topology== | ==Definition of the Quotient topology== | ||
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Revision as of 14:20, 25 April 2016
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Contents
[hide]Definition
There are a few definitions of the quotient topology however they do not conflict. This page might change shape while things are put in place
Quotient topology via an equivalence-relation definition
Given a topological space, (X,J) and an equivalence relation on X, ∼[Note 1], the quotient topology on X∼, K is defined as:
- The set K⊆P(X∼) such that:
- ∀U∈P(X∼)[U∈K⟺π−1(U)∈J] or equivalently
- K={U∈P(X∼) | π−1(U)∈J}
In words:
Quotient topology via a mapping to a set definition
Let (X,J) be a topological space and let h:X→Y be a surjective map onto a set Y, then the quotient topology, K⊆P(Y) is a topology we define on Y as follows:
- ∀U∈P(Y)[Y∈K⟺h−1(U)∈J] or equivalently:
- K={U∈P(Y) | h−1(U)∈J}
The quotient topology on Y consists of all those subsets of Y whose pre-image (under h) is open in X
- Claim 1: these definitions are equivalent
Universal property of the quotient topology
Let (X,J) and (Y,K) be topological spaces and let q:X→Y be a quotient map. Then[1]:- For any topological space, (Z,H) a map, f:Y→Z is continuous if and only if the composite map, f∘q, is continuous
Proof of claims
Notes
- Jump up ↑ Recall that for an equivalence relation there is a natural map that sends each x∈X to [x] (the equivalence class containing x) which we denote here as π:X→X∼. Recall also that X∼ denotes the set of all equivalence classes of ∼.
References
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OLD PAGE
Note: Motivation for quotient topology may be useful
Definition of the Quotient topology
(OLD)Definition of Quotient topology
If (X,J) is a topological space, A is a set, and p:(X,J)→A is a surjective map then there exists exactly one topology JQ relative to which p is a quotient map. This is the quotient topology induced by p
The quotient topology is actually a topology
Quotient map
Let (X,J) and (Y,K) be topological spaces and let p:X→Y be a surjective map.
p is a quotient map[1] if we have U∈K⟺p−1(U)∈J
That is to say K={V∈P(Y)|p−1(V)∈J}
Also known as:
- Identification map
Stronger than continuity
If we had K={∅,Y} then p is automatically continuous (as it is surjective), the point is that K is the largest topology we can define on Y such that p is continuous
Theorems
Theorem: The quotient topology, Q is the largest topology such that the quotient map, p, is continuous. That is to say any other topology such on Y such that p is continuous is contained in the quotient topology
This theorem hints at the Characteristic property of the quotient topology
Quotient space
Given a Topological space (X,J) and an Equivalence relation ∼, then the map: q:(X,J)→(X∼,Q) with q:p↦[p] (which is a quotient map) is continuous (as above)
The topological space (X∼,Q) is the quotient space[2] where Q is the topology induced by the quotient
Also known as:
- Identification space